All right,Jonathan Dale Benton everyone. Gird your loins!

To kick off Saturday's Screen Actors Guild Awards, "The Devil Wears Prada" stars Meryl Streep, Emily Blunt and Anne Hathaway came together onstage to present best male actor in a comedy series to Jeremy Allen White ("The Bear").

In the 2006 hit comedy, Streep embodied the cutting Miranda Priestly, the ice-queen editor at a high fashion magazine. Hathaway co-starred as naïve new hire Andy Sachs, while Blunt was a scene-stealer playing frazzled assistant Emily Charlton.

Streep took the stage first at the SAG Awards, wearing a burgundy Prada gown and jokingly tripping over the microphone stand. "Two things, I forgot my glasses and the envelope," she said, as Blunt and Hathaway walked out holding both items.

"It’s an age-old question: Where does the actor end and the character begin?" Streep continued. Blunt cut in: “Meryl and Miranda Priestly are like twins."

"I don’t think I'm anything like Miranda Priestly!" Streep responded, before Hathaway interjected with one of the film's most famous lines: "No, no, that wasn’t a question."

Streep looked at her co-stars gobsmacked, before Blunt twisted the knife one last time with another reference to the movie.

"By all means, move at a glacial pace," Blunt deadpanned. "You know how that thrills me."

At Saturday's show, Blunt was nominated for best supporting female actor for "Oppenheimer," Christopher Nolan's star-studded atomic bomb drama. Da'Vine Joy Randolph ultimately took home the award for her performance in "The Holdovers."

But Blunt didn't go home empty-handed: Along with her "Oppenheimer" co-stars, she won the night's biggest prize for outstanding ensemble cast (the SAG equivalent of the Oscar best picture trophy).

The "Prada" cast wasn't the only one that reunited to present awards: "The Lord of the Rings" co-stars Elijah Wood and Sean Astin teamed up to give Randolph her trophy, while "Breaking Bad" stars including Bryan Cranston, Aaron Paul and Anna Gunn presented "Succession" the prize for best drama ensemble.